Now lets take the information we need from this and plug it into the following equation which is the characteristic equation for an Euler Cauchy equation thats second order.
Where we get b and c knot from
So this means that if x2 has some coefficient or didn't match this form, we'd have to adjust the equation to make the first term x2. In this case though its fine, and we just have to find b(x) and c(x), which are
b(x) = -3
c(x) = 4
which means that our equation will be
Which after factoring becomes
So r is equal to 2 twice, which means its a repeated result, one of the possibilities. Now the general solution to the Euler Cauchy equation is x to the n where n is the solution, but in this case we have a repeated result. This means we need to add an additional factor of ln(x) into our solution giving us the following.
Which is our final result assuming there's no initial conditions.
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