Resistance

ΔV = -IR

R=ρl/a

Where rho is the resistivity due to impediments in the material, multiplied against the length, divided by the area.

Pressure

ΔP = IR

This is the change in pressure due to an increase in resistance. We can visualize this increase in pressure by thinking about water flow through a pipe. Let us think about a large pipe transitioning to a smaller one. The change in pressure from the area before the small pipe to after the small pipe can be approximated by thinking about the smaller pipe as a resistive element, similar to resistance in a current. However instead of impediments as a function of the material, it is just the smaller size of the pipe. Therefore the resistance in this case would be proportional to (1/A) where A is the area of the smaller pipe.

## No comments:

## Post a Comment